Question

Solve the equation in the complex number system. X^2+x+8=0

(Simplify your answer. Type an exact answer, using radicals and i as needed. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)

Answer 1

Explanation:

here's a step-by-step explanation with more detail:

The equation X^2 + X + 8 = 0 can be solved using the Quadratic Formula:

X = (-b ± √(b^2 - 4ac)) / 2a,

where a = 1, b = 1, and c = 8.

Plugging in the values, we get:

X = (-1 ± √(1^2 - 4 * 1 * 8)) / 2 * 1

X = (-1 ± √(-31)) / 2

Since the square root of a negative number is not a real number, the solution to the equation must be expressed using complex numbers. In this case, the square root of -31 can be expressed as the imaginary unit i times the square root of 31.

X = (-1 ± i * √31) / 2

So, the two solutions to the equation are:

X = (-1 + i * √31) / 2 and X = (-1 - i * √31) / 2

And these are the two solutions expressed in terms of the imaginary unit i.