Question

A gas has a volume of 350 ml at 45°C. If the volume changes to 400 ml, what is the new

temperature? (answer in °C)

Answer 1

88.42°C

Step-by-step explanation:

The temperature change of a gas can be calculated using Gay-Lussac's law, which states that the pressure-volume ratio of a gas is directly proportional to its temperature. The equation is:

P1/V1 = P2/V2 = (nRT)/V = constant

where P1 and V1 are the initial pressure and volume, P2 and V2 are the final pressure and volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Given the initial volume and temperature, we can rearrange the equation to solve for the final temperature:

T2 = (P1V1)/(nR) * (V2/P1)

Since the pressure is constant, we can simplify the equation to:

T2 = T1 * (V2/V1)

We can convert the temperature to Kelvin:

T1(K) = 45 + 273.15 = 318.15 K

T2(K) = T1 * (400/350) = 318.15 * (400/350) = 361.57 K

Finally, we can convert back to Celsius:

T2(°C) = 361.57 - 273.15 = 88.42 °C

The new temperature is 88.42°C.


ALLEN

Answer 2

The new temperature of the gas can be calculated using the ideal gas law: PV = nRT. Rearranging the equation to solve for temperature, we get: T = (PV)/(nR). With a volume of 400 ml, a pressure of 1 atm, and a constant R of 0.08206 L·atm/K·mol, the new temperature of the gas is 59.95°C.