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5 votes
Fully reduce the radical question using prime factorization technique:


\sqrt250h^4k^5

THANK YOU SO MUCH I APPRECIATE IT

User Hotfix
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2 Answers

3 votes

Answer:

<--> V 250h4k5

√(2 × 5 × 5 × 5) × (h×h×h×

[ take out one of the pair ~]

5 xhxhxkx k√2 × 5 × k

--> 5h2k2✓10k

User Jonathan Porter
by
7.8k points
6 votes


{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~


\qquad \sf&nbsp; \dashrightarrow \: \sqrt{250 {h}^(4) {k}^(5) }


\qquad \sf&nbsp; \dashrightarrow \: √((2 * 5 * 5 * 5) * (h * h * h * h )* (k * k * k * k * k) )

[ take out one of the pair ~ ]


\qquad \sf&nbsp; \dashrightarrow \: 5 * h * h * k * k √(2 * 5 * k)


\qquad \sf&nbsp; \dashrightarrow \: 5 {h}^(2) {k}^(2) √(10k)

That's our simplified answer ~

User Flower
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