The given equation can be solved using the Quadratic Formula. The Quadratic Formula states that for an equation of the form ax2 + bx + c = 0, the solutions are x = [-b ± √(b2 - 4ac)]/2a.
In this case, a = 2, b = 11, and c = 13. Plugging these values into the Quadratic Formula yields: x = [-11 ± √(112 - 4(2)(13))]/2(2). Simplifying this expression gives us x = [-11 ± √(121)]/4.
Solving for the two solutions yields x = [-11 ± 11]/4, or x = [-11 + 11]/4 and x = [-11 - 11]/4. Simplifying further, we get x = 0 and x = -2. Therefore, the two real solutions to the given equation are x = 0 and x = -2, in simplest form.