Question

A patient with respiratory alkalosis has a blood plasma pH of 7.57. What is the [OH−] of the blood plasma?Express your answer to two significant figures and include the appropriate units.

Answer 1

The [OH−] is 3.7x10-7M.

Step-by-step explanation:

1st) Using the pH value (7.57) and the relation between pH and pOH, we have to calculate the pOH of the blood plasma:

`\begin{gathered} pH+pOH=14 \\ 7.57+pOH=14 \\ pOH=14-7.57 \\ pOH=6.43 \\ \end{gathered}`

2nd) Now with the pOH value (6.43) and the formula of pOH, we can calculate the [OH−] :

`\begin{gathered} pOH=-log\lbrack OH^-\rbrack \\ 6.43=-log\lbrack OH^-\rbrack \\ 10^((-6.43))=\lbrack OH^-\rbrack \\ 3.7*10^(-7)M=\lbrack OH^-\rbrack \end{gathered}`

So, the [OH−] is 3.7x10-7M.