Question

Picture in the box findiing the average

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Answer 1

`\cfrac{6}{4+√(2)}\implies \cfrac{6}{4+√(2)}\cdot \cfrac{4-√(2)}{4-√(2)}\implies \cfrac{6(4-√(2))}{\underset{\textit{difference of squares}}{(4+√(2))(4-√(2))}} \implies \cfrac{6(4-√(2))}{(4)^2 - (√(2))^2} \\\\\\ \cfrac{6(4-√(2))}{16 - 2}\implies \cfrac{6(4-√(2))}{14}\implies \cfrac{3(4-√(2))}{7}\implies \cfrac{12-3√(2)}{7}`