Question

A suspect has two months of unpaid fees. One month they had 3 parking tickets and 14 traffic violations totaling $2030.The second month they had 11 parking tickets and 11 traffic violations totaling $2200 . How much does each parking ticket cost? How much does each traffic violation cost?

Answer 1

-727.41 dollars

Explanation:

To find the cost of each parking ticket and each traffic violation, we can set up a system of two equations. Let's call the cost of a parking ticket "x" and the cost of a traffic violation "y".

For the first month:

3x + 14y = 2030

For the second month:

11x + 11y = 2200

We can solve for x and y using any method, such as substitution or elimination. For this problem, let's use substitution.

First, we'll solve for x in the first equation:

3x + 14y = 2030

3x = 2030 - 14y

x = (2030 - 14y) / 3

Next, we'll substitute this expression for x into the second equation:

11x + 11y = 2200

11((2030 - 14y) / 3) + 11y = 2200

2030 - 14y + 11y = 2200 * 3 / 11

2030 - 3y = 636

-3y = -1394

y = 464.67

Finally, we'll substitute this value of y back into the first equation to find x:

3x + 14y = 2030

3x + 14(464.67) = 2030

3x = 2030 - 6544.68

x = (2030 - 6544.68) / 3

x = -2180.23 / 3

x = -727.41

So each parking ticket costs approximately -727.41 dollars, and each traffic violation costs approximately 464.67 dollars. However, since these values are negative, it means the suspect has received a credit rather than being charged for these fees.

Answer 2

each parking ticket costs $100 and each traffic violation costs $124.28.

Explanation:

To find out the cost of each parking ticket and each traffic violation, we can set up two equations using the information given:

Let x be the cost of each parking ticket.

In the first month, 3 parking tickets cost 3x, and 14 traffic violations cost 14y.

The total cost for the first month is 2030, so we have:

3x + 14y = 2030

In the second month, 11 parking tickets cost 11x, and 11 traffic violations cost 11y.

The total cost for the second month is 2200, so we have:

11x + 11y = 2200

Now that we have two equations, we can use substitution to find the value of x and y.

From the first equation, we can solve for y:

y = (2030 - 3x) / 14

Substituting this expression for y into the second equation:

11x + 11((2030 - 3x) / 14) = 2200

Expanding the expression for y and simplifying the equation:

11x + 2030 - 33x / 14 = 2200

Multiplying both sides by 14:

154x + 28420 = 30800

Solving for x:

x = $100

So each parking ticket costs $100, and each traffic violation costs:

y = (2030 - 3x) / 14 = (2030 - 3 * 100) / 14 = (2030 - 300) / 14 = 1730 / 14 = $124.28

Therefore, each parking ticket costs $100 and each traffic violation costs $124.28.