Answer:
7275lb
Explanation:
Let R be the number of refrigerators and P be the number of pianos. The total weight of the load can be represented as:
Weight = 300R + 475P
The weight must be less than or equal to 6500lb, so we have the inequality:
300R + 475P <= 6500
To graph this inequality, we can first rewrite it in slope-intercept form:
475P <= 6500 - 300R
P <= (6500 - 300R) / 475
Next, we can plot the points (0, 13.68), (22, 0) on the coordinate plane, where (0, 13.68) corresponds to the y-intercept and (22, 0) corresponds to the x-intercept. The graph will be a line that starts at the y-intercept and goes down to the right, passing through (22, 0).
The truck could carry up to 22 refrigerators (when R = 22, P = 0), or up to 13.68 pianos (when R = 0, P = 13.68), or any combination of refrigerators and pianos that results in a weight of less than or equal to 6500lb.
As for the specific case of 10 refrigerators and 9 pianos, the weight can be calculated as:
Weight = 300 * 10 + 475 * 9 = 3000 + 4275 = 7275
This would overload the truck, as the weight of 7275lb is greater than the maximum allowed weight of 6500lb.