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Pls help asap it’s annoying me

Pls help asap it’s annoying me-example-1
User Imbichie
by
8.4k points

2 Answers

3 votes

Answer:

b. 53.1°

c. 126.9⁰

Explanation:

These are SSA triangles; use Law of Sines to find the unknown angle:

b) sin30/15 = sinA/24

sinA(15) = sin30(24)

sinA = sin30(24)/15 = 0.80

m∠A = sin⁻1(0.80) = 53.1°

c) m∠A = 180 - 53.1 = 126.9⁰

User Bnil
by
7.3k points
1 vote

Answer:

∠ BAC = 53.13° , ∠ BAC = 126.87°

Explanation:

using the Sine rule in Δ ABC


(a)/(sinA) =
(c)/(sinC)

where a is the side opposite ∠ A and c is the side opposite ∠ C

here a = BC = 24 and c = AB = 15 , then


(24)/(sinA) =
(15)/(sin30) ( cross- multiply )

15 sinA = 24 sin30° ( divide both sides by 15 )

sin A =
(24sin30)/(15) , then

A =
sin^(-1) (
(24sin30)/(15) ) = 53.13°

(b)

acute angle BAC = 53.13°

(c)

the sine of an angle is positive in both the first and second quadrant , so

obtuse angle BAC = 180° - 53.13° = 126.87°

User Amitfr
by
7.0k points