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3 Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O

In the above equation how many moles of water can be made when 41 moles of HNO3 are consumed?

User Iamkhush
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1 Answer

1 vote

Answer:

5.125 moles of water

Step-by-step explanation:

Given the reaction:

Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O

When 41 moles of HNO3 are consumed, we can calculate the number of moles of water produced using the stoichiometric coefficients in the balanced chemical equation.

According to the coefficients, 1 mole of Cu reacts with 8 moles of HNO3 to produce 4 moles of H2O. Therefore, when 41 moles of HNO3 are consumed, we can calculate the number of moles of water produced as follows:

41 moles HNO3 / 8 moles HNO3 per mole H2O = 5.125 moles H2O

So, 5.125 moles of water can be made when 41 moles of HNO3 are consumed.

User Gerrie
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