Question

Factorise: 16x4 - y4

Answer 1

Step-by-step explanation:
`16x^(4) -4y^(4) = (4x^(2) )^(2) -(2y^(2) )^(2)= (4x^(2) + 2y^(2) )(4x^(2) - 2y^(2))`

identity used =

`(a^(2) -b^(2) ) = (a+b)(a-b)`

Answer 2

= (4x^2 + y^2)(2x + y)(2x - y).

Explanation:

16x^4 - y^4

= (4x2)^2 - (y^2)^2

= (4x^2 +y^2)(4x^2 - y^2)

=(4x^2 + y^2)( (2x)^2 -y^2)

= (4x^2 + y^2)(2x + y)(2x - y).