Answer:
y = -1/3 x + 3
Explanation:
To find the equation of the line that passes through the two points (-3,4) and (3,2) in slope-intercept form, we'll first find the slope of the line using the formula:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) and (x2, y2) are the two given points.
Plugging in the given points, we get:
m = (2 - 4) / (3 - (-3)) = -2 / 6 = -1/3
Next, we'll use the point-slope form of a line to find the equation of the line:
y - y1 = m(x - x1)
where (x1, y1) is one of the given points, and m is the slope of the line.
We'll use the first given point, (-3,4), so we have:
y - 4 = -1/3 (x - (-3))
Expanding the right side of the equation, we get:
y - 4 = -1/3 x + 1
Finally, we'll rearrange the equation to get it in slope-intercept form, which is:
y = -1/3 x + b
where b is the y-intercept. To find b, we'll plug in one of the given points and solve for b:
y = -1/3 x + b
4 = -1/3 * (-3) + b
4 = 1 + b
b = 4 - 1
b = 3
So the equation of the line in slope-intercept form is:
y = -1/3 x + 3