Question

A student runs the reaction represented by the equation below. What mass of H2 gas would be produced if the student begins with 9.68 grams of each reactant? Round to the nearest 0.01 and remember to include both units and substance in your answer!!!

Zn + HCl --> ZnCl2 + H2

Answer 1

The balanced equation for the reaction is:

Zn + 2HCl -> ZnCl2 + H2

Since the student starts with 9.68 grams of each reactant, we have 9.68 grams of Zn and 9.68 grams of HCl.

From the balanced equation, we know that 2 moles of HCl are needed to produce 1 mole of H2. Thus, if we have 9.68 grams of HCl, we have:

9.68 g / (36.5 g/mol) = 0.265 moles of HCl

Therefore, we can calculate the number of moles of H2 that would be produced:

0.265 moles H2 = 0.265 moles HCl x (1 mole H2 / 2 moles HCl) = 0.132 moles of H2

Next, we can convert the number of moles of H2 to mass:

0.132 moles H2 x (2.02 g/mol) = 0.267 g of H2

Therefore, 9.68 grams of each reactant would produce approximately 0.267 g of H2.

So the answer is 0.267 g of H2.