Question

A rock is thrown upward with a velocity of 14

meters per second from the top of a 50
meter high cliff, and it misses the cliff on the way back down. When will the rock be 2
meters from ground level? Round your answer to two decimal places.

Answer 1

The rock will be 2 meters from the ground after 1.29 seconds.

Step-by-step explanation:

The motion of the rock can be described by the following kinematic equation:

h = vi * t + 0.5 * a * t^2

where h is the height of the rock above the ground, vi is the initial velocity (14 m/s), t is time, and a is the acceleration due to gravity (-9.8 m/s^2).

Setting h = 2 m and solving for t, we get:

2 = 14 * t + 0.5 * (-9.8) * t^2

Expanding and solving for t, we get:

t = 1.29 seconds

So, the rock will be 2 meters from the ground after approximately 1.29 seconds.