Answer:
(a) To determine the mean and standard deviation of Y, we need to find the expected value and standard deviation of the number of defects that can be sold by Company F. Since the number of defects that can be sold is equal to X if X is less than or equal to 2, and equal to 2 if X is greater than 2, we can use the following formula to find the expected value of Y:
E(Y) = P(X = 0) × 0 + P(X = 1) × 1 + P(X = 2) × 2 + P(X > 2) × 2
E(Y) = 0.58 × 0 + 0.23 × 1 + 0.11 × 2 + 0.03 × 2
E(Y) = 0.23 + 0.22 + 0.03
E(Y) = 0.48
To find the standard deviation of Y, we can use the following formula:
Var(Y) = P(X = 0) × (0 - E(Y))^2 + P(X = 1) × (1 - E(Y))^2 + P(X = 2) × (2 - E(Y))^2 + P(X > 2) × (2 - E(Y))^2
Var(Y) = 0.58 × (0 - 0.48)^2 + 0.23 × (1 - 0.48)^2 + 0.11 × (2 - 0.48)^2 + 0.03 × (2 - 0.48)^2
Var(Y) = 0.58 × 0.2304 + 0.23 × 0.1024 + 0.11 × 0.0304 + 0.03 × 0.0304
Var(Y) = 0.1333
The standard deviation of Y is the square root of the variance:
StdDev(Y) = √Var(Y)
StdDev(Y) = √0.1333
StdDev(Y) = 0.3663
So, the mean and standard deviation of Y are 0.48 and 0.3663, respectively.
(c) To find the mean and standard deviation of the selling price for the fat quarters sold by Company G, we need to find the expected value and standard deviation of the price, taking into account the discount for each defect. We can use the following formula to find the expected value of the price:
E(Price) = $5.00 - $1.50 × E(Defects)
E(Price) = $5.00 - $1.50 × 0.40
E(Price) = $5.00 - $0.60
E(Price) = $4.40
To find the standard deviation of the price, we can use the following formula:
StdDev(Price) = $1.50 × StdDev(Defects)
StdDev(Price) = $1.50 × 0.66
StdDev(Price) = $0.99
So, the mean and standard deviation of the selling price for the fat quarters sold by Company G are $4.40 and $0.99, respectively.