Question

What is the equation of the line that passes through the point (-3,1)(−3,1) and has a slope of \frac{2}{3}

3

2

​

?

Answer 1

y = (2/3)x + 3

Explanation:

first we need to find the y-intercept

we can do this by using what is given, the point (-3,1) and the slope (2/3)

using the slope-intercept formula: y = mx + b.

m = slope

b = y intercept

we can plug in the x and y values we were given

so,

1 = (2/3)(-3) + b

we can now easily solve for b

1 = (2/3)(-3) = b

first multiply

1 = -2 + b

then add 2 to both sides, this way we isolate b

3 = b

now that we have the y intercept we can write the equation of the line

y = (2/3)x + 3

if you really wanted to, you can check if this is correct by plugging in the point again and seeing if the equation is true.

1 = (2/3)(-3) + 3

multiply first

1 = -2 + 3

add the like terms

1 = 1