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Part 6 Computation (12 points) 1. Calculate the average atomic mass of Iron using the chart provided. (6pts) Isotopic symbol 54Fe 56Fe 57 Fe 58Fe Natural Abundance (%) 5.8 91.7 2.2 0.3​

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Answer:

84.066 amu

Step-by-step explanation:

The average atomic mass of iron can be calculated using the following formula:

Average atomic mass = (54Fe * 0.058 + 56Fe * 0.917 + 57Fe * 0.022 + 58Fe * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)

Plugging in the numbers, we get:Average atomic mass = (54 * 0.058 + 56 * 0.917 + 57 * 0.022 + 58 * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)

Average atomic mass = (31.12 + 51.592 + 1.254 + 0.174) / (0.058 + 0.917 + 0.022 + 0.003)

Average atomic mass = 84.066 / (0.058 + 0.917 + 0.022 + 0.003)Average atomic mass = 84.066 / 1

Average atomic mass = 84.066So, the average atomic mass of Iron is 84.066 atomic mass units (amu).

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