Answer:
84.066 amu
Step-by-step explanation:
The average atomic mass of iron can be calculated using the following formula:
Average atomic mass = (54Fe * 0.058 + 56Fe * 0.917 + 57Fe * 0.022 + 58Fe * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)
Plugging in the numbers, we get:Average atomic mass = (54 * 0.058 + 56 * 0.917 + 57 * 0.022 + 58 * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)
Average atomic mass = (31.12 + 51.592 + 1.254 + 0.174) / (0.058 + 0.917 + 0.022 + 0.003)
Average atomic mass = 84.066 / (0.058 + 0.917 + 0.022 + 0.003)Average atomic mass = 84.066 / 1
Average atomic mass = 84.066So, the average atomic mass of Iron is 84.066 atomic mass units (amu).