Question

Need helpppp with this problem!! thanks!

Answer 1

20

Explanation:

`\sqrt[3]{64xy^(3)}` =
`\sqrt[3]{64}` ×
`\sqrt[3]{x}` ×
`\sqrt[3]{y^(3)}`

a = coefficient

=
`\sqrt[3]{64}`

∴a = 4

`x^(b)` =
`x^(-2)`×
`\sqrt[3]{x}`

=
`x^(-2)`×
`x^{(1)/(3)}`

=
`x^{-2+(1)/(3)}`

=
`x^{(-6)/(3) + (1)/(3)}`

=
`x^{(-6+1)/(3)}`

`x^(b)` =
`x^{-(5)/(3)}`

∴b =
`-(5)/(3)`

`y^(c)` =
`y^(-4)`×
`\sqrt[3]{y^(3)}`

=
`y^(-4)`×
`(y^(3))^{(1)/(3)}`

=
`y^(-4)` ×
`y`

=
`y^(-4 + 1)`

`y^(c)` =
`y^(-3)`

∴c =
`-3`

∴Product of a, b and c =
`(4)`×
`(-(5)/(3))`×
`(-3)`

= 20