Answer:
Explanation:
For example, we have 8, which is not a perfect square
square root of(8)
we divide 8 by prime numbers, until it gets to 1
8/2
4/2
2/2
1
We have divided our number 8 with 2 by 3 times.
Now we pair the numbers.
2 with 2, and the third 2 remains.
the pairs will be in front of the squareroot, and what remains will remain in the squareroot.
squareroot(8) = 2

Let's take another number
32
Divide it in prime numbers
32/2
16/2
8/2
4/2
2/2
1
We have 2 pairs of 2 and on remaining 2
We multiply the pairs together, and we get 4 in front of the squareroot.
squareroot(32) = 4

Let's take 21
21/7
3/3 (3 is a prime number also 5,7,11,13,17 etc)
1
-This one doesn't have a short answer that could be written.
take 80
80/2
40/2
20/2
10/2
5/5
1
We have 2 pairs of 2 and a 5
squareroot(80) = 4
