Question

You are fixing the roof of your house when a hammer breaks loose and slides down. The roof makes an angle of 45 ∘ with the horizontal, and the hammer is moving at 4.5 m/s when it reaches the edge. Assume that the hammer is moving from the top of the roof to its right edge.

A. What is the horizontal component of the hammer's velocity just as it leaves the roof?
B. What is the vertical component of the hammer's velocity just as it leaves the roof?

Answer 1

A. The horizontal component of the hammer's velocity just as it leaves the roof can be calculated by multiplying the velocity of the hammer by the cosine of the angle of the roof with the horizontal:

Vhorizontal = V * cos(45) = 4.5 m/s * cos(45) = 3.16 m/s

B. The vertical component of the hammer's velocity just as it leaves the roof can be calculated by multiplying the velocity of the hammer by the sine of the angle of the roof with the horizontal:

Vvertical = V * sin(45) = 4.5 m/s * sin(45) = 3.16 m/s

Step-by-step explanation: