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In the equation:

Na₂CO3 + 2HCI → 2NaCl + H₂O + CO₂
How many moles of HCI are required to produce 15.91 g of CO₂

1 Answer

3 votes

Answer:

0.7244 moles of HCI

Step-by-step explanation:

To solve for the number of moles of HCI required to produce 15.91 g of CO₂, we need to use the balanced equation of the reaction:

Na₂CO₃ + 2HCI → 2NaCl + H₂O + CO₂

From the equation, we can see that 1 mole of Na₂CO₃ reacts with 2 moles of HCI to produce 1 mole of CO₂.

Since the desired amount of CO₂ is 15.91 g, we can convert it to moles:

15.91 g / 44.01 g/mol = 0.3622 mol CO₂

And since 1 mole of Na₂CO₃ reacts with 2 moles of HCI to produce 1 mole of CO₂, then 0.3622 mol CO₂ is produced from 0.3622 * 2 = 0.7244 moles of HCI.

Therefore, 0.7244 moles of HCI are required to produce 15.91 g of CO₂.

User Ricardo Cruz
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