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Given 3. 82g of (NH4)2O find how many atoms of (NH4)2O
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Given 3. 82g of (NH4)2O find how many atoms of (NH4)2O

User Ryan Pergent
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1 Answer

4 votes

Answer: 4.41*10^23 atoms

Step-by-step explanation:

3.82*(6.02*10^23)/52.10= 4.41*10^23 atoms

N*2=14.01*2=28.02

H*8= 1.01*8= 8.08

O*1=16.00*1=16.00

Add them together to get 52.10 g

User RBR
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