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Ralph has a cylindrical container of parmesan cheese. The diameter of the base of the container is 2.75 inches, and the height is 6 inches. What is the area of a horizontal cross section of the cylinder to the nearest tenth of a square inch? Use 3.14 for π

User Dlitwak
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1 Answer

21 votes
21 votes

ANSWER

5.9 inches

Step-by-step explanation

We have to find the area of the horizontal cross-section of the cylinder.

The horizontal cross-section of a cylinder is the shape that you get when you slice through a cylinder horizontally.

That is:

Therefore, we have to find the area of the circular shape.

The area of a circle is given as:


A\text{ = }\pi\cdot r^2

where r = radius

From the question, the diameter is 2.75 inches. Since radius is half of the diameter, the radius is:

r = d / 2 = 2.75 / 2

r = 1.375 inches

Therefore, the cross-sectional area is:


\begin{gathered} A\text{ = }\pi\cdot(1.375)^2 \\ A\text{ = 5.9 inches} \end{gathered}

That is the answer.

Ralph has a cylindrical container of parmesan cheese. The diameter of the base of-example-1
User Jamie F
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