Question

A right triangle has side length 8 15 and 17 use these lengths to find Cos M Tan M and Sin M

Answer 1

Cos A:
`(15)/(17)`

Tan A:
`(8)/(15)`

Sin C:
`(8)/(17)`

How I did it:

Cos A:
`(Base)/(Hypotenuse)` This is the basic " fraction "

Or in similar terms: =
`(ab)/(bc)`

Cos A =
`(15)/(17)`

Tan A =
`(Perpendicular)/(Base)`

Similar terms once again =
`(ac)/(ab)`

Tan A =
`(8)/(15)`

Sin A =
`(Perpendicular)/(Hypotnuse)`

Similar terms =
`(ac)/(bc)`

Since A =
`(8)/(17)`

Thus your answers are:

Cos A =
`(15)/(17)`

Tan A =
`(8)/(15)`

Sin A =
`(8)/(17)`