Question

Peter has a total of 22 nickels and dimes. There is a total of $1.80. Which of the following is a possible combination of coins that Peter has?

Answer 1

Answer: 8 nickels and 14 dimes

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Work Shown:

n = number of nickels

22-n = number of dimes

5n = value of the nickels in cents

10(22-n) = value of the dimes in cents

5n+10(22-n) = total value in cents

5n+10(22-n) = 180

5n+220-10n = 180

-5n+220 = 180

-5n = 180-220

-5n = -40

n = -40/(-5)

n = 8 is the number of nickels

22-n = 22-8 = 14 is the number of dimes

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Check:

8 nickels = 8*5 = 40 cents

14 dimes = 14*10 = 140 cents

8 nickels + 14 dimes = 40 cents + 140 cents = 180 cents = $1.80

8 nickels + 14 dimes = 22 coins total

The answers are confirmed.