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What is the minimum value of y=x^2+36/5

User IMOBAMA
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4 votes

Answer:

(36/5)

Explanation:

y=x^2+36/5

Since x is squared, the result will always be a positive number, regardless of the actual value of x. Starting with a value of x of zero, the x^2 term will only grow as one moves away from 0. E.g., (-1)^2 = 1, (-2)^2 = 4, etc.

So the minium for this equation will occur when x = 0. It only gets larger from that point. The minimum is (36/5).

See the attached graph.

What is the minimum value of y=x^2+36/5-example-1
User Muhasturk
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