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A line contains the points P (-1, 4) and Q (-4, -2). Write the equation of the line in the slope-intercept form.

A.y = 2x + 6
B.y = 6x + 2
C.y = 3x - 4
D.y =2x + 2

User Igal S
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1 Answer

4 votes

Answer:

Explanation:

Given points are P(-1,4) and Q(-4,-2)

we know that slope m between two points (x1,y1) and (x2,y2) is m=y2-y1/x2-x1

so,slope m between points P and Q is m=-2-4/-4-(-1)

m=-6/-3

m=2

Now,we know that equation of line

with slope m having points (x1,y1) and (x2,y2) is y-y1=m(x-x1)

so equation of line between P and Q is y-4=2(x+1)

y-4=2x+ 2

y=2x+6

User DaveBurns
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