Question

Suppose we have a bag of jelly beans 82% of the jelly beans orange, 14% are black, and 4% are green. Moreover, 15% of orange are sugar free, 70% of black beans are sugar free, and 90% of green beans are sugar free Suppose we select a jelly bean at random.

1. Construct a tree diagram to represent this situation

2. Find the probability of green bean and sugar free

3. Given the bean is sugar free, what is the probability that it is an orange bean?


Please I need help

Answer 1

3/50

Explanation:

3 g, 5 r, 2 o

3 + 5 + 2 = 10

Orange = 2 jelly beans

Probability of selecting an orange jelly bean: 2/10 or 1/5

If you put the jelly bean back in, there is still 10 jelly beans.

Green = 3 jelly beans

Probability of selecting a green jelly bean: 3/10\

Multiply the probabilities:

1/5 x 3/10

= 3/50