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A simple circuit contains a 9 V battery connected with wires to a small light bulb. If the current through the bulb is 0.025 A, what is the resistance of the bulb?

Group of answer choices

360 ohms

15 ohms

127 ohms

0.225 ohms

User EugeneMi
by
7.7k points

1 Answer

5 votes

Answer:


\huge\boxed{\sf R = 360\ ohms}

Step-by-step explanation:

Given data:

Potential Difference = V = 9 V

Current = I = 0.025 A

Required:

Resistance = R = ?

Formula:

V = IR (Ohm's Law)

Solution:

V = IR

Divide I to both sides


\displaystyle (V)/(I) = R

Put the given data

9/0.025 = R

360 ohms = R

OR

R = 360 ohms


\rule[225]{225}{2}

User Cups
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