132k views
1 vote
How many moles of lithium fluoride (LiF) are present in a 39 gram sample?

1 Answer

6 votes

Answer:


\huge\boxed{\sf n = 1.5\ mol}

Step-by-step explanation:

Given data:

Mass = m = 39 g

Molar mass = M = 7 + 19 = 26 g/mol

Required:

No. of moles = n = ?

Formula:


\displaystyle n = (m)/(M)

Solution:

Put the given data in the above formula.

n = 39/26

n = 1.5 mol


\rule[225]{225}{2}

User Zijun
by
8.8k points