Question

Needs E15,000 on his

E16,000 so on. Until what age will he have enough money G
(4marks)
Q171
Amal, Balu and Chandran each has some sweets, Amal gives one third of his sweets to
Balu. Balu gives one third of all the sweets he now has to Chandran. Then Chandran gives
one third of all the sweets he now has to Amal. All of them end up having the same
number of sweets, Chandran begins with 40 sweets, How many sweets does Balu have
originally?
(4marks

Answer 1

Answer: Balu originally had 40 sweets.

Explanation:

Let x be the number of sweets Balu originally had.

After Amal gives one third of his sweets to Balu, Balu's number of sweets becomes x + (1/3)x = (4/3)x.

After Balu gives one third of his sweets to Chandran, Chandran's number of sweets becomes 40 + (1/3)(4/3)x = 40 + (1/3)x.

After Chandran gives one third of his sweets to Amal, Amal's number of sweets becomes (2/3)x + (1/3)(40 +(1/3)x) = (2/3)x + (1/3)x + 40/3 = (5/3)x + 40/3.

Since all three of them now have the same number of sweets, we can set the number of sweets each of them has equal:

(4/3)x = (5/3)x + 40/3.

Now, we will isolate x by rearranging the equation. Subtracting (5/3)x from both sides, we get:

(4/3)x - (5/3)x = 40/3

Simplifying the left side:

-x/3 = 40/3

Dividing both sides by -1/3:

x = 40

Thus, Balu originally had 40 sweets.