Question

A line has a slope of -2/3 and passes through the point (6, -10). What is the equation of the line?

Answer 1

= 3y-2x+18=0

Explanation:

Gradient (m) = -2/3

The equation of the line is given by the formula

`= (y - y1)/(x - x1) = m`

Point = (6,-10)

y1 = -10

x= 6.

note// y and x were not given .

=

`= (y - ( - 10))/(x -6) = ( - 2)/(3) \\ = (y + 10)/(x - 6) = ( - 2)/(3) \\ = 3(y + 10) = - 2(x - 6) \\ = 3y + 30 = - 2x + 12 \\ = 3y = - 2x + 12 - 30 \\ = 3y = 2x - 18 \\ = 3y - 2x + 18 = 0`

therefore the equation of the line = 3y-2x+18=0