Question

For the reaction below, how many moles of aluminum are produced from 14 moles of

lithium?
3Li (s) + AI(NO3)3 (aq) --> 3LINO3(aq) + Al(s)

Answer 1

4.67 moles of aluminum

Step-by-step explanation:

For the reaction:

3Li (s) + AI(NO3)3 (aq) --> 3LiNO3(aq) + Al(s)

The number of moles of aluminum produced from 14 moles of lithium can be determined by using the mole ratio between aluminum and lithium in the balanced chemical equation. The mole ratio between aluminum and lithium in the reaction is 1:3, which means that for every 3 moles of lithium, 1 mole of aluminum is produced. Therefore, the number of moles of aluminum produced from 14 moles of lithium can be calculated as follows:

14 moles of Li / 3 moles of Li per mole of Al = 4.67 moles of Al

So, 14 moles of lithium will produce 4.67 moles of aluminum.