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What is an equation of the line that passes through the points (2,-2) and (3,-4)?

2 Answers

1 vote
The answer is y=-2x+2
Step-by-step explanation:
Points are given as (2,-2) & (3,-4)
From if the equation of line:
m=y2-y1/x2-x1
m= -4-(-2)/3-2= -2/1=-2, m=-2
User Dsh
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6.7k points
3 votes

Answer:

y = -2x + 2

Step-by-step explanation:

An equation of a line can be found in slope-intercept form, y = mx + b, where m is the slope of the line and b is the y-intercept. To find the slope (m), you can use the formula:

m = (y2 - y1) / (x2 - x1)

Where (x1, y1) and (x2, y2) are the coordinates of the two points. Substituting the values from the given points, we get:

m = (-4 - (-2)) / (3 - 2) = -2 / 1 = -2

Next, to find the y-intercept (b), we can use either one of the given points and the slope to substitute in the equation y = mx + b. For example, using the point (2, -2), we get:

-2 = -2 * 2 + b

Solving for b, we get:

b = -2 + 4 = 2

So, the equation of the line in slope-intercept form is:

y = -2x + 2

User Tutorialfeed
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