Question

5. A diff-jumper of mass 68.0 kg stands on the edge of a cliff and possesses 16,800 J of potential energy.

How high up is this lunatic from the base of the cliff?
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Answer 1

Step-by-step explanation:

To determine the height of the cliff, we can use the formula for potential energy:

PE = mgh

where m is the mass of the object (68.0 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff.

Rearranging the formula to solve for h:

h = PE / (mg)

h = 16,800 J / (68.0 kg * 9.8 m/s^2)

h = 16,800 J / 658.4 N

h = 25.5 meters

Therefore, the diff-jumper is 25.5 meters high from the base of the cliff.