Answer:
Step-by-step explanation:
Here is a step by step explanation of how to solve the problem:
Break the initial velocity into x and y components. The velocity of the Pokéball can be broken down into two components: the horizontal component (vix) and the vertical component (viy). The horizontal component remains constant throughout the motion and has a value of vix = vcosθ, where v is the magnitude of the velocity and θ is the angle of launch. The vertical component changes due to the acceleration of gravity and has a value of viy = vsinθ - gt, where t is time.
Solve for the time of flight. We want to find the time it takes for the Pokéball to reach its maximum height, so we need to set viy = 0 and solve for t:
0 = vsinθ - gt
gt = vsinθ
t = vsinθ / g
Calculate the maximum height. The maximum height is reached when the vertical component of velocity is equal to zero, so we can use the equation:
h = viy^2 / (2g)
h = (vsinθ)^2 / (2g)
Calculate the range. The range is the horizontal distance traveled by the Pokéball during its flight, and it can be found using the equation:
x = vix * t
x = vcosθ * (vsinθ / g)
Draw a well labeled diagram of the physical situation. Draw the coordinate axes, showing the directions, and label the initial velocity as a vector. Show the trajectory of the Pokéball, including the point where it reaches its maximum height, and label the acceleration due to gravity.