Question

A park has two rectangular, fenced playgrounds. The first playground has a perimeter of 160 feet. The second playground is twice as long and twice as wide as the first playground. Which of these could be the perimeter of the second playground in feet? pls help now ty

a. 640

b. 320

c. 240

d. 168

Answer 1

So, the answer is (b) 320 feet.

Explanation:

Let's call the length and width of the first playground "x".

The perimeter of the first playground is 160 feet, so 2 times the length plus 2 times the width is equal to 160:

2x + 2x = 160

Simplifying:

4x = 160

Dividing both sides by 4:

x = 40

So the length and width of the first playground are both 40 feet.

The second playground is twice as long and twice as wide as the first playground, so the length and width of the second playground would be 2 * 40 = 80 feet.

The perimeter of the second playground would then be 2 * 80 + 2 * 80 = 320 feet.

So, the answer is (b) 320 feet.