Question

What is the new pressure if you expand 103.0 liters of air at 2.00 atm into a cylinder whose volume is 156.0 liters?

a
0.504 atm
b
2.33 atm
c
1.32 atm
d
3.03 atm

Answer 1

Step-by-step explanation:

The new pressure can be calculated using the Ideal Gas Law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant (8.31 J/mol*K), and T is the temperature (assumed to be constant).

Since the number of moles of gas and temperature is constant, we can rearrange the equation to solve for the new pressure:

P = (NRT) / V

Using the initial conditions of P1 = 2.00 atm and V1 = 103.0 liters, we can find the new pressure P2 after the expansion to 156.0 liters:

P2 = (P1 * V1) / V2 = (2.00 atm * 103.0 liters) / 156.0 liters = 1.30 atm

Therefore, the new pressure is 1.30 atm, and the correct answer is (c) 1.32 atm.