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For 3y-2x=-18 determine the value of y when x = 0, and the value of x when y = 0

User Jsaddwater
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1 Answer

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3y-2x=-18
3y-2(0)=-18 (sub in x with 0 to find y)
3y=-18 (anything times 0 is 0)
Divide both sides of the equation by 3 to get y alone
Y=-6

3y-2x=-18
3(0)-2x=-18 (sub in y with 0 to find y)
-2x=-18 (anything times 0 is 0)
Divide both sides of the equal sign by -2 to get x alone
X=9 (negative divided by a negative will become positive)

Hope this helps!!
User Cloudsurfin
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