Question

hi i need some help with this problem can you help me?find the value of x in this equation...1/3(6x-5)-x=1/3-2(x+1)

Answer 1

x = 0

Step-by-step explanation:

We want to solve

`(1)/(3)\mleft(6x-5\mright)-x=(1)/(3)-2(x+1)`

for x.

Now expanding both sides gives

`(6x)/(3)-(5)/(3)-x=(1)/(3)-2x-2`

now further simplification gives

`((6)/(3)x-x)-(5)/(3)=(1)/(3)-2x-2`
`\Rightarrow x-(5)/(3)=(1)/(3)-2x-2`

Now adding 5/3 to both sides gives

`x=(1)/(3)-2x-2+(5)/(3)`

then adding 2x to both sides gives

`x+2x=(1)/(3)+(5)/(3)-2`
`\Rightarrow3x=(6)/(3)-2`
`3x=2-2`
`3x=0`
`\Rightarrow\boxed{x=0}`

which is our answer!