Question

NO LINKS!! URGENT HELP PLEASE!!

For #4-6, find the area of each figure, round your answer to one decimal point if necessary.

Answer 1

Problem 4

Answer: 2400 square inches

Step-by-step explanation:

Draw a horizontal divider line to split the figure into two rectangles.

The rectangle up top is 30 by 30, so it has area 30*30 = 900 square inches.

The rectangle on the bottom has area 50*30 = 1500 square inches.

total = 900+1500 = 2400 square inches

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Problem 5

Answer: 12 square inches

Step-by-step explanation:

Draw a horizontal divider line to split the figure into two rectangles.

A = area of rectangle on top = 2*2 = 4 square inches

B = area of rectangle on bottom = 4*2 = 8 square inches

C = total = A+B = 4+8 = 12 square inches

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Problem 6

Answer: 2592 square yards

Step-by-step explanation:

Draw a horizontal divider line to get two rectangles.

A = area of rectangle on top = 36*36 = 1296 square yards

B = area of rectangle on bottom = 72*18 = 1296 square yards

C = total = A+B = 1296+1296 = 2592 square yards.

You have the correct answer. Nice work.

Answer 2

4) 2400 in²

5) 12 in²

6) 2592 yd²

Step-by-step explanation:

To calculate the area of each given composite figure, divide the figure into two rectangles and sum the area of the two rectangles.

`\boxed{\begin{minipage}{5cm}\underline{Area of a rectangle}\\\\$A=w\cdot l$\\\\where:\\ \phantom{ww} $\bullet$ \quad $w$ is the width.\\ \phantom{ww} $\bullet$ \quad $l$ is the length.\\\end{minipage}}`

Question 4

Separate the figure into two rectangles by drawing a horizontal line (see attachment).

`\begin{aligned}\textsf{Total Area}&=\textsf{Area 1}+\textsf{Area 2}\\&= 30\cdot 30+50\cdot 30\\&=900+1500\\&=2400\; \sf in^2\end{aligned}`

Question 5

Separate the figure into two rectangles by drawing a horizontal line (see attachment).

`\begin{aligned}\textsf{Total Area}&=\textsf{Area 1}+\textsf{Area 2}\\&=2 \cdot 2+ 4\cdot2 \\&=4+8\\&=12\; \sf in^2\end{aligned}`

Question 6

Separate the figure into two rectangles by drawing a horizontal line (see attachment).

`\begin{aligned}\textsf{Total Area}&=\textsf{Area 1}+\textsf{Area 2}\\&=36 \cdot36 +72 \cdot18 \\&=1296+1296\\&=2592 \; \sf yd^2\end{aligned}`