Question

NO LINKS!! URGENT HELP PLEASE!!

Find the shaded area of each figure, and round your answer to one decimal place if necessary. #4-6

Answer 1

38 & 27 & 147

Explanation:

4) 38cm²

5*4 = 20cm²

2*9 = 18cm²

5) 27m²

6*6 = 36m²

3*3 = 9m²

6) 147in²

14*14 = 196cm²

7*7 = 49in²

Answer 2

4) 38 cm²

5) 27 m²

6) 147 in²

Explanation:

To calculate the area of each given figure, subtract the area of the cut-out rectangle (marked in blue on the attached diagram) from the area of the larger rectangle.

`\boxed{\begin{minipage}{5cm}\underline{Area of a rectangle}\\\\$A=w\cdot l$\\\\where:\\ \phantom{ww} $\bullet$ \quad $w$ is the width.\\ \phantom{ww} $\bullet$ \quad $l$ is the length.\\\end{minipage}}`

Question 4

`\begin{aligned}\textsf{Total Area}&=\textsf{Larger rectangle}-\textsf{Cut-out rectangle}\\&=9 \cdot 6- (9-5)\cdot 4\\&=9 \cdot 6- 4\cdot 4\\&=54-16\\&=38\; \sf cm^2\end{aligned}`

Question 5

`\begin{aligned}\textsf{Total Area}&=\textsf{Larger rectangle}-\textsf{Cut-out rectangle}\\&= 6\cdot 6- 3\cdot 3\\&=36-9\\&=27\; \sf m^2\end{aligned}`

Question 6

`\begin{aligned}\textsf{Total Area}&=\textsf{Larger rectangle}-\textsf{Cut-out rectangle}\\&= 14\cdot 14- 7\cdot 7 \\&=196-49\\&=147\; \sf in^2\end{aligned}`