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A milkman boils milk before distributing it in pots. He raises the temperature of the milk from 10 degrees Celsius to 130 degrees Celsius with the thermal energy of 120000 J. If the mass of the milk Is 25000 g. the specific heat capacity of the milk would be

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Answer: The specific heat capacity of the milk is 0.24 J/g°C.

Step-by-step explanation:

The specific heat capacity (C) of a substance is defined as the amount of heat energy required to raise the temperature of a unit mass of the substance by one degree Celsius. To find the specific heat capacity of the milk in this case, we need to divide the total heat energy added to the milk (120000 J) by the change in temperature of the milk (120 degrees Celsius) and the mass of the milk (25000 g).

Using this formula, the specific heat capacity of the milk can be calculated as follows:

C = (120000 J) / (25000 g * 120°C)

C = (120000 J) / (25000 g * 120 K) (converting Celsius to Kelvin)

C = 0.24 J/g°C

So, the specific heat capacity of the milk is 0.24 J/g°C.

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