Question

Which is equivalent to h⋅h⋅h⋅j⋅j⋅h⋅j?

h4⋅j3, 4h⋅3j, 7(h⋅j), or (h⋅j)7?

Answer 1

Hi your answer would be h^4*j^3

Step-by-step explanation:
There are 4 H’s being multiplied by themselves meaning it’s H to the 4th power then it’s the same process with J; J to the 3rd power. Finally you’d multiply H to the 4th and J to the 3rd. I hope this helps :)

Answer 2

Answer: h^4*j^3

Step-by-step explanation:

h*h*h*h = h^4

j*j*j = j^3

thus answer is h^4 * j^3