Final answer:
The probability of spinning a red followed by a green, assuming equal chances for each color, is ⅓ multiplied by ⅓, resulting in a combined probability of ⅙. The numerator in this fraction, when expressed in lowest terms, is 1.
Step-by-step explanation:
To calculate the probability of spinning a red then a green on the spinner twice, we need to know the individual probabilities of each occurring. Without the exact probabilities of spinning red or green given in the question, we will assume that the probabilities are fair and the spinner is equally divided into these colors. Therefore, since there are two spins involved, the probability of the first event (spinning a red) and the second event (spinning a green) must be multiplied to find the combined probability.
Let P(Red) be the probability of spinning red and P(Green) the probability of spinning green. If the spinner has equal sectors, and we're assuming there are only three colors mentioned (red, blue, green), the probability P(Red) is 1/3 and P(Green) is also 1/3.
The combined probability of two independent events is found by multiplying the probabilities of each event occurring separately:
P(Red, Green) = P(Red) * P(Green) = ⅓ * ⅓ = ⅙
The probability of spinning a red then a green, expressed as a fraction in lowest terms, is 1/9. So the numerator in this fraction is 1.