Question

A small black cloth bag holds two red counters, two green counters, two

blue counters, and two black counters. All are the same size. Without
looking into the bag, what is the probability of drawing a red counter then
a black counter from the bag without replacement? *

Answer 1

1/14

Explanation:

P(red, then black) =
`(2)/(8)` ·
`(2)/(7)` =
`(4)/(56)` =
`(1)/(14)` (simplifed form)