Question

A triangle has vertices on a coordinate grid at P(-6, -8), Q(-6, 7), andR(-2,7). What is the length, in units, of PQ?

Answer 1

Given:

The coordinates of point P, (x1, y1)=(-6,-8).

The coordinates of point Q, (x2, y2)=(-6,7).

Now, the expression for the length of PQ is,

`PQ=\sqrt[]{(x2-x1)^2+(y2-y1)^2}`

Substitute the values.

`\begin{gathered} PQ=\sqrt[]{(-6-(-6))^2+(7-(-8))^2} \\ PQ=\sqrt[]{0+(15)^2} \\ PQ=15 \end{gathered}`

Therefore, the length of PQ is 15.