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Find the volume, in liters of 8.00 g O₂ at STP?

User Jeanmartin
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1 Answer

7 votes

Answer: V = 5.60 L

Step-by-step explanation:

At STP (standard temperature and pressure) are the following values.

T = 273K of 0°C

P = 1.00 atm

R is the gas constant.

R = 0.08206 L atm/K mol

To find the volume in liters we will use PV = nRT.

Step 1: Convert 8.00 g O₂ to moles O₂.

8.00 g O₂ x (1 mol O₂/32.00 g O₂) = 0.250 mol O₂

Step 2: Rearrange PV = nRT to isolate V.

V = nRT/P

Step 3: Insert the known values into the equation and solve for V.

V = [(0.250 mol O₂) x (0.08206 L atm/ K mol) x 273K] / 1.00 atm

V = 5.60 L

Note that all units cancel except for L.

User Vijay Tholpadi
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