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Which of the following represents the integrated rate law for a zero-order reaction?

[A]t - [A]o = - kt
k = Ae(-Ea/RT)

User Jperl
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1 Answer

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Answer: [A]t = -kt + [A]₀ or when you rearrange the equation [A]t - [A]₀ = -kt

Step-by-step explanation:

Below are the integrated rate laws for zero, first and second order reactions.

Zero Order

[A]t = -kt + [A]₀

First Order

ln[A]t = -kt + ln[A]₀

Second Order

1/[A]t = kt + 1/[A]₀

K = Ae^-(Ea/RT) is the Arrhenius equation

User Francisco Meza
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